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Question

xdx2axx2=ansin1[xa1]. The value of n is:you may use dimensional analysis to solve the problem

A
0
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B
-1
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C
1
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D
none of these
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Solution

The correct option is C 1
We know,

sin1 is dimensionless quantity.

And,

[xa]= dimensionless.

[x]=[a],

In LHS,

Dimension is =[a]

And in RHS,

Dimension is =[a]n

Hence it is clear that n=1

Option C is the correct answer

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