wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

ex[2+sin2x1+cos2x]dx=

A
extanx+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
ex+tanx+ey
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
e2xtanx+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
extan2x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A extanx+c
ex[2+sin2x1+cos2x]dx

ex[2+2sinxcosx2cos2x]dx

=ex(sec2x+tanx)dx

And , ex(f(x)+f(x))dx=exf(x)+c

Here also, ddxtanx=sec2x

Hence, integration results to:-

=extanx+c

Hence, answer is option-(A).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Transformations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon