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Byju's Answer
Standard XII
Mathematics
Standard Formulae - 3
∫1+√tan x1+ta...
Question
∫
(
1
+
√
t
a
n
x
)
(
1
+
t
a
n
2
x
)
2
t
a
n
x
d
x
equal to
A
1
2
(
l
o
g
t
a
n
x
)
+
√
t
a
n
x
+
c
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B
(
l
o
g
t
a
n
2
x
)
+
1
2
√
t
a
n
x
+
c
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C
l
o
g
|
t
a
n
x
|
+
2
√
t
a
n
x
+
c
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D
l
o
g
|
t
a
n
x
|
+
√
t
a
n
x
+
c
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Solution
The correct option is
A
1
2
(
l
o
g
t
a
n
x
)
+
√
t
a
n
x
+
c
∫
1
2
s
i
n
x
c
o
s
x
d
x
+
1
2
∫
√
t
a
n
x
s
i
n
x
c
o
s
x
d
x
=
1
2
∫
s
i
n
2
x
+
c
o
s
2
x
s
i
n
x
c
o
s
x
d
x
+
1
2
∫
s
e
c
2
x
√
t
a
n
x
d
x
=
1
2
l
o
g
(
t
a
n
x
)
+
√
t
a
n
x
+
c
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0
Similar questions
Q.
∫
{
1
+
2
t
a
n
x
(
t
a
n
x
+
s
e
c
x
)
}
1
/
2
d
x
=
Q.
Integration of sec x is: