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Question

(1+tan x)(1+tan2x)2 tan xdx equal to

A
12(log tan x)+tan x+c
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B
(log tan2x)+12tan x+c
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C
log|tan x|+2tan x+c
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D
log|tan x|+tan x+c
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Solution

The correct option is A 12(log tan x)+tan x+c
12 sin x cos xdx+12tan xsin x cos xdx=12sin2x+cos2xsin x cos xdx+12sec2xtan xdx=12log(tan x)+tan x+c

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