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Question

(1+tanx)(1+tan2x)2tanxdx equal to

A
logtan2x+tanx+c
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B
logtan2x+12tanx+c
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C
log|tanx|+2tanx+c
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D
log|tanx|+tanx+c
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Solution

The correct option is C logtan2x+tanx+c

12sinxcosxdx+12tanxsinxcosxdx=12sin2x+cos2xsinxcosxdx+12sec2xtanxdx=log(tan2x)+tanx+c

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