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Question

sinxcosxcos2x+3cosx+2dx

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Solution

let cosx=t
sinxdx=dt
sinxcoxcos2x+3cosx+2dx=tt2+3t+2dx=(t+2)2(t+1)(t+1)(t+2)dt
=1t+1dt21t+2
=ln(t+1)2ln(t+2)+c
=lnt+1(t+2)2+c
=lncosx+1(cosx+2)2+c

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