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B
−150(1+5x10)3/2+c
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C
−175(1+5x10)3/2+c
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D
−175(1+5x10)5/2+c
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Solution
The correct option is C−175(1+5x10)3/2+c ∫√5+x10x10.1x11dx=∫√1+5x10.1x11dx=−150∫√1+5x10.d(1+5x10)=−150⎧⎪
⎪⎨⎪
⎪⎩(1+5x10)3/232⎫⎪
⎪⎬⎪
⎪⎭+c=−175(1+5x10)32+c