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Question

x4+11+x6 dx=

A
tan1(x)tan1(x3)+c
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B
tan1(x)13tan1(x3)+c
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C
tan1(x)+tan1(x3)+c
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D
tan1(x)+13tan1(x3)+c
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Solution

The correct option is D tan1(x)+13tan1(x3)+c
I=x4+11+x6 dx=(x4x2+1)+x2(1+x6) dx=x4x2+11+x6 dx+x21+x6 dx=11+x2 dx+133x21+x6 dx=tan1(x)+13tan1x3+c

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