Question

$\int \frac{x-sinx}{1+cosx}dx=xtan\left(\frac{x}{2}\right)+plog\left|sec\left(\frac{x}{2}\right)\right|+c\Rightarrow p=$

• A. -4
• B. 4
• C. 2
• D. -2

Answer 1

The correct option is A

-4

$I=\int (\frac{x}{2}se{c}^2\frac{x}{2}-tan\frac{x}{2})dx$
$I=xtan\frac{x}{2}-4log\left|sec\frac{x}{2}\right|+c$
$\Rightarrow p=-4$