You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Engineering Mathematics

Stoke's Theorem

∫∫ ∇× P.ds, w...

Question

$\int \int (\nabla \times P)$ .ds, where P is a vector , is equal to

\oint P . d l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\oint \nabla \times \nabla \times P . d l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\oint \nabla \times P . d l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

∭ \nabla . P d v

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\oint P . d l$
By Stoke's Theorem
$\oint \to P . d l = \iint (\nabla \times \to P) . d s$

Suggest Corrections

Similar questions

▽ \times ▽ \times P

(where

P

is a vector) is equal to

Q. Which of the following vector is/are equal to vector AB, where A(0,0) and B(1,1).

Q. The vectors

\to x

and

\to y

satisfy the equation

p \to x + q \to y = \to a

(where

p, q

are scalar constants and

\to a

is a known vector). It is given that

\to x . \to y \geq \frac{| \to a |^{2}}{4 p q}

, then

\frac{| \to x |}{| \to y |}

is equal to (

p q > 0

)

Q. If

\to a, \to b, \to c

are three non-coplanar vectors, and

\to p, \to q, \to r

are reciprocal vectors to

\to a, \to b, \to c

respectively, then

(l \to a + m \to b + n \to c) . (l \to p + m \to q + n \to r)

is equal to

: (

where

l, m, n

are scalars

)

Q. The vectors

\to x

and

\to y

satisfy the equation

p \to x + q \to y = \to a

(where

p, q

are scalar constants and

\to a

is a known vector). It is given that

\to x . \to y \geq \frac{| \to a |^{2}}{4 p q}

, then

\frac{| \to x |}{| \to y |}

is equal to (

p q > 0

)

Join BYJU'S Learning Program

∫∫(∇×P).ds, where P is a vector , is equal to

The correct option is A ∮P.dlBy Stoke's Theorem ∮→P.dl=∬(∇×→P).ds

$\int \int (\nabla \times P)$ .ds, where P is a vector , is equal to

The correct option is A $\oint P . d l$
By Stoke's Theorem
$\oint \to P . d l = \iint (\nabla \times \to P) . d s$