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Question

(ex)x(2+logx)dx=....+c,xR+{1}

A
xx
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B
(ex)x
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C
ex
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D
(1+logx)(ex)x
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Solution

The correct option is C (ex)x
(ex)x(2+logx)dx=(ex)xdx+ex.xx(1+logx)dx
Integrating by parts ,
(ex)x+ex(xx(1+logx))(ddx(ex).(xx(1+logx)dx))dx
(ex)x+exxx(ex)x
(ex)x

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