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Byju's Answer
Standard XII
Physics
Antiderivative
t √ t +√ t / ...
Question
∫
(
t
√
t
+
√
t
t
2
)
d
t
is equal to
A
2
(
√
t
−
1
√
t
)
+
c
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B
2
(
√
t
+
1
√
t
)
+
c
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C
2
(
1
√
t
−
√
t
)
+
c
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D
2
(
√
t
+
2
√
t
)
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Solution
The correct option is
A
2
(
√
t
−
1
√
t
)
+
c
∫
(
t
√
t
+
√
t
t
2
)
d
t
=
∫
1
√
t
d
t
+
∫
√
t
t
2
×
√
t
√
t
d
t
=
∫
1
√
t
d
t
+
∫
1
t
√
t
d
t
∫
t
−
1
/
2
d
t
+
∫
t
−
3
/
2
d
t
=
t
(
−
1
2
+
1
)
(
−
1
2
+
1
)
+
t
(
−
3
2
+
1
)
(
−
3
2
+
1
)
=
2
√
t
−
2
√
t
+
c
=
2
(
√
t
−
1
√
t
)
+
c
∫
(
t
√
t
+
√
t
t
2
)
d
t
=
2
(
√
t
−
1
√
t
)
+
c
Suggest Corrections
1
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