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Question

π/20sinxcosx1+sinxcosxdx

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Solution

(π2)0(sin(π2x)cosx(π2x)1+sin(π2x)cosx(π2x))dx=(π2)0(cosxsinx1+cosxsinx)dx=(π2)0(cosxsinx1+cosxsinx)dxI=I2I=0thenI=0


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