Question

$\underset{-1}{\overset{1}{\int }}{e}^{x}dx=$

Answer 1

We know that $\int e^{x}dx=e^x$

$\Rightarrow \underset{-1}{\overset{1}{\int }}{e}^{x}dx=[e^x{]}_{-1}^1$

$\Rightarrow e^1-e^{-1}$

$\Rightarrow e-\frac{1}{e}$

By taking L.C.M we get,

$\Rightarrow \frac{e^2-1}{e}$