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Question

221x2dx is equal to

A
4
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B
2
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C
2
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D
0
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Solution

The correct option is B 4
22|1x2|dx

12(1x2)dx+11(1x2)dx+21(1x2)dx

[x+x33]12+[xx33]11+[x+x33]21

[1132+83]+[113+113]+[2+83+113]

[1+73+2231+73]

[123]=4


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