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Question

ba1(xa)(bx)dx,d>a

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Solution

badx(xa)(bx)
when x=a,c=asin2θ+bcos2θ
acos2θ=bcos2θcosθ=π/2
when x,=b,
b=asin2θ+bcos2θ=0
0π/22sinθcosθ(ab)(ba)cos2θ(ba)sin2θ
0π/22sinθcosθ(ab)(ba)sinθcosθ
=(ab)×2×π/2
=π(ba)

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