-40 log sin x-cos x-cos x dx

I=∫_0^π/4log(1+tan x) =∫_0^π/4log(1+tan (π/4 4))=log2∫_0^π/41dx 1 ∴ 2l=π/4log2 ...

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Integration Using Substitution

∫π/40 log si...

Question

$\frac{π}{4} \int 0 l o g (\frac{s i n x + c o s x}{c o s x}) d x$

$\frac{π}{4} l o g 2$

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$\frac{π}{2} l o g 2$

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$\frac{π}{8} l o g 2$

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$L o g 2$

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Solution

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Similar questions

If $A = \int_{0}^{π} \frac{s i n x}{s i n x + c o s x} d x$

$B = \int_{0}^{π} \frac{s i n x}{s i n x - c o s x} d x$

\int \frac{cos \sqrt{x}}{\sqrt{x}} d x =

I = \int c o s^{- 1} \sqrt{x} d x

J = \int \frac{s i n^{- 1} \sqrt{x} - c o s^{- 1} \sqrt{x}}{s i n^{- 1} \sqrt{x} + c o s^{- 1} \sqrt{x}} d x

\int_{0}^{\frac{π}{2}} \frac{c o s x}{1 + c o s x + s i n x} d x =

\int_{0}^{π} \frac{t a n x}{s e c x + c o s x} d x =

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