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(logx)2dx

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Solution

(logx)2dx
Let dv=dxv=x
u=(logx)2du=2logx×dxx
=x(logx)2x×2logx×dxx
=x(logx)22logxdx
Let u=logxdu=1xdx and dv=dxv=x
=x(logx)22[xlogxx×dxx]
=x(logx)22xlogx+2dx
=x(logx)22xlogx+2x+c where c is the constant of integration.


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