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Question

(log x)2 dx=

A
x(log x)22x log x2x+c
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B
x(log x)22x log xx+c
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C
x(log x)22x log x+2x+c
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D
x(log x)22x log x+x+c
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Solution

The correct option is C x(log x)22x log x+2x+c
(log x)2 dx
Put log x=tet=xdx=et dt, then it reduces to t2.et dt=t2et2 tet+2et+c=x(log x)22x log x+2x+c

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