$\int s e c (11 + 12 x) t a n (11 + 12 x) d x$

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Solution

We have,

$I = \int sec (11 + 12 x) tan (11 + 12 x) d x$

Now, using formula,

$\int sec x tan x d x = sec x + C$

Therefore,

$I = \int sec (11 + 12 x) tan (11 + 12 x) d x$
$= \frac{sec (11 + 12 x)}{12} + C$

Hence, this is the answer

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