The correct option is D cos2x2 +c integral sinx is cosx +cso integral sin2x will be cos2x/2 +c ...

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Conjugate of a Complex Number

∫ sin2xdx

Question

$\int s i n 2 x d x$

c o s 2 x + c

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l o g c o s x + c

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\frac{- c o s 2 x}{2} + c

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- s i n x + c

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Solution

The correct option is D $\frac{- c o s 2 x}{2} + c$
integral sinx is -cosx +c
so integral sin2x will be -cos2x/2 +c

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