I = ∫^√(2)_√(2)1 41xx^2 + 2 Both limit are salve so #160; I = 0 #160; #160; #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integration of Irrational Algebraic Fractions - 2

∫√2√21- 41xx2...

Question

$\int_{\sqrt{2}}^{\sqrt{2}} \frac{1 - 41 x}{x^{2} + 2}$

Open in App

Solution

$I = \int_{\sqrt{2}}^{\sqrt{2}} \frac{1 - 41 x}{x^{2} + 2}$
Both limit are salve so
$I = 0$ $★$

Suggest Corrections

Similar questions

${lim}_{x \to 2} (\frac{1}{x - 2} - \frac{2}{x^{2} - 2 x})$

x = {(2 + \sqrt{5})}^{1 / 2} + {(\sqrt{5} - 2)}^{1 / 2}

y = {(2 + \sqrt{5})}^{1 / 2} - {(\sqrt{5} - 2)}^{1 / 2}

x^{2} + y^{2}

{log}_{[(2 / 3) | x - 2 |]} 2^{(1 - x^{2})} \geq 0

{lim}_{x \to 2} (\frac{1}{x - 2} - \frac{4}{x^{2} - 4})

l t_{x \to 2} (\frac{1}{x - 2} - \frac{4}{x^{2} - 4})

Join BYJU'S Learning Program