Question

int x = 10, y = 5;
void abc (int y)
{
y= y + x;
printf("%d", y);
}
void main ( )
{
int x = 2;
x = x + y;
abc(x);
printf("%d", x);
}
What is the ouput of the following program?

• A. 10, 10
• B. 17, 10
• C. 17, 7
• D. 7, 10

Answer 1

The correct option is C 17, 7

Step 1: Global variables 'x' initialized with 10, 'y' initialized with 5.
Step 2: In main function we have local variable 'x' and it has value '2'
Step 3: In main function x = x + y will update value of 'x' of main function and 'x' becomes 7
Step 4: The function call abc(x) will carry '7' and that value copied into 'y' variable of abc ( )
Step 5: y = y+ x in abc ( ) will update 'y' variable value 17 because 'x' in abc( ) is global the print function in abc ( ) prints 17 and print function in main print 7.