Question

int x=2;
int f(int x, int *p)
{
*p = x+3;
x = *p;
return x;
}
void main ( )
{
x = 5;
x=f(x, & x);
printf("%d",x)
}
Output of the above program is

• A. 2
• B. 8
• C. 6
• D. 5

Answer 1

The correct option is B 8

Step 1: Global variable initialized with value '2' assume its address starts with 100



Step 2: main( ) updates global variable 'x' with '5' and f(x, & x) will pass values of x, address of x as arguments to called function. So local variables of f() are x, p containing values of global variable 'x' and address of global variable 'x' respectively. So *p=x+3 will update global variable 'x' with 8. And that value assigned to local variable 'x' of f().

$\therefore$ return 'x' of f() will return '8' and this '8' will be initialized to Global variables 'x' so printf statement will print '8' output.