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Question

Evaluate :010π|sinx|dx


A

20

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B

8

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C

10

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D

18

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Solution

The correct option is A

20


Evaluating the integral :

The period of |sin(x)| is π

100π|sin(x)|dx

sin(x) is always positive when 0<x<π then |sin(x)| =sin(x)

100πsin(x)dx

10-cos(x)0π

-10cos(π)+10cos(0)20[cos(π)=-1,cos(0)=1]

Hence, option (A) is the correct answer.


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