∫11+cosaxdx=
cotax2+c
1atanax2+c
1acosecax-cotax+c
1acosecax+cotax+c
Explanation for the correct option:
Finding the value of the given integral:
The given equation is
∫11+cosaxdx=∫12cos2ax2dxsincecosax=2cos2ax2-1=12∫sec2ax2dx=12tanax2a2+c=1atanax2+c
Thus, the correct answer is option (B).