Evaluate:∫dx(x2+4x+13)
log(x2+4x+3)+c
13tan-1(x+2)3+c
log(2x+4)+c
[2x+4][x2+4x+13]2+c
Explanation for correct option:
Evaluating the integral
∫dxx2−4x+13=∫dxx2−2×2×x+22-4+13=∫dx(x−2)2−4+13∵a2-2×a×b+b2=(a-b)2=∫dx(x−2)2+9=∫dx(x−2)2+(3)2=13tan-1(x-2)3+c
Hence, option (B) is correct.