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Question

Integrate
(4x+2)x2+x+1dx

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Solution

Let I=(4x+2)x2+x+1dx
Let x2+x+1=t(4x+2)dx=2dt
So, I=2tdt=2(t)3/2(3/2)+c
I=43t3/2+c
So, I=43(1+x+x2)3+c

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