Question

Integrate and find the value of the integral
$\underset{-2}{\overset{4}{\int }}(\frac{x}{2}+3)dx$

• A. 21
• B. 22
• C. 23
• D. 24

Answer 1

The correct option is A 21

Let the integral be $I$
$I=\underset{-2}{\overset{4}{\int }}(\frac{x}{2}+3)dx$
$I={[\frac{x^2}{4}+3x+C]}_{-2}^4$
Applying Limits,
$I=[\frac{16}{4}+12+C]-[\frac{4}{4}-6+C]$
$I=16+5=21$