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Question

Integrate by using suitable substitution
(1). 32s ds
(2). csc(vπ2)cot(vπ2)dv
(3). 2ππθdθ
(4). x0xsinx2dx

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Solution

1)32sds=(32s)32(2).32+c=13(32s)32+c

2)csc(vπ2)cot(vπ2)dv=2csc(vπ2)+c

3)2ππθdθ=12[4π2π2]=3π22

4)x0xsinx2dx=12[sinx2]x0=12sinx

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