Question

Integrate: $\frac{dy}{dx}=(x^3+x+1)$ w.r.t $x$

Answer 1

Given : $\frac{dy}{dx}=(x^3+x+1)$

$\int dy=\int (x^3+x+1)dx$

$y=\frac{x^4}{4}+\frac{x^2}{2}+x+c$

Where c is the constant of integration.