Integrate - e2x-1e2x-1

∫e^2x 1e^2x+1 dx = ∫e^x 1e^xe^x + 1e^x dx ∫e^x e^ xe^x + e^2 dx e^x + e^ x = t ⇒ dx. [e^x e^ x] = dt ∫dtt = log | t | + c = log (e^x + e^ x ...

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Special Integrals - 1

Integrate : ...

Question

Integrate :
$\frac{e^{2 x} - 1}{e^{2 x} + 1}$

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Solution

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Similar questions

\frac{d x}{[1 - e^{2 x}]^{(} 1 / 2)}

\frac{e^{2 x} - 1}{e^{2 x} + 1}

\frac{e^{2 x} - e^{- 2 x}}{e^{2 x} + e^{- 2 x}}

Integrate the following functions.
$\int \frac{e^{2 x} - 1}{e^{2 x} + 1} d x .$

\frac{e^{2 x} - e^{- 2 x}}{e^{2 x} + e^{- 2 x}}

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