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Question

Integrate 10sin1(2x1+x2)dx

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Solution

Let,
I=10sin1(2x1+x2)dx
Let x=tanθ
dx=sec2θdθ
When, x=0,θ=0 & x=1,θ=π4
Now,
I=π402θ.sec2θ.dθ
Integrating by parts , Taking sec2θ as a first function.
=π2log2

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