Integrate:
∫dx / (sin2x⋅cos2x) equals?
Consider the given integration,
⇒∫dx / sin2x.cos2x
⇒∫4dx/ 4sin2x.cos2x
⇒∫4dx/ (2sinx cosx )2 = ∫4dx/ (sin 2x )2
⇒4∫cosec22x dx
⇒4(−cot2x)/2+C
⇒−2cot2x+C
Hence, this is the answer.