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Question

Integrate:x2+x+53x+2dx

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Solution

x2+x+53x+2dx
x23x+2dx+x3x+2dx+53x+2dx
(x329+49(3x+2))dx
I1=x3dx+29dx+49(3x+2)dx
x2629x+4913x+2dx
49.3ln|3x+2|
I2:x3x+2dx
19(U2U)dv
19U29ln|u|19((3x+2)2ln/3x+2)
I353x+2dx
=53ln|3x+2|
I=x262x9+427ln|3x+2|+19(3x+22n(3x+2)+53ln|3x+2|
x26+19x+4327ln|3x+2|+29

1124753_1140072_ans_898072f179f04a3297e6ad1f5e7d5b53.jpg

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