Question

Integrate $\int {\tan }^{2}xdx$

Answer 1

Given : $\int {\tan }^{2}xdx$

Let $I=\int {\tan }^{2}xdx$

$\int ta{n}^{2}xdx=\int ({\sec }^{2}x-1)dx$

$I=\int {\sec }^{2}xdx-\int dx$

$I=\tan x-x+c$