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Question

Integrate:
3x+5(x+1)(x2)2dx

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Solution

Let 3x+5(x+1)(x2)2=Ax+1+Bx2+C(x2)2
On comparing, we get
A=29, B=29, C=113
So, (3x+5)(x+1)(x2)2dx=29(x+1)dx+29(x2)dx+113(x2)2dx
So, 3x+5(x+1)(x2)2=29log|x+1|29ln(x2)1131(x2)+C

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