Question

Integrate

$\int (\sec x\tan x+\frac{3}{x}-4)dx$

Answer 1

$\int (\text{sec}x\tan x+\frac{3}{x}-4)dx=\int \text{sec}x\tan xdx+3\int \frac{1}{x}dx-4\int dx=\tan x+3\ln x-4x+c$