wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Integrate sinxcosxdx.


Open in App
Solution

Calculate the given expression:

Given, sinxcosxdx

Let, I=sinxcosxdx

Let, sinx=t

Differentiating both sides with respect to x,

cosx=dtdxcosxdx=dt

I=tdt[sinx=t,cosxdx=dt]I=t22+C[xn=xn+1n+1]I=sin2x2+C

Therefore,sin(x)cos(x)dx=sin2(x)2+C.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon