Question

Integrate:
${\tan }^{4}x$

Answer 1

$\int ta{n}^{4}xdx=\int ta{n}^{2}x(se{c}^{2}x-1)dx=\int ta{n}^{2}xse{c}^{2}dx-\int ta{n}^{2}xdx=\int ta{n}^{2}xse{c}^{2}xdx-\int (se{c}^{2}x-1)dx=\left(\frac{ta{n}^{3}x}{3}\right)-tanx+x+C$