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Question

Integrate the following function: (logx)2x

A
(logx)22+c
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B
(logx)33+c
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C
(logx)42+c
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D
(logx)53+c
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Solution

The correct option is C (logx)33+c
log2xxdx.

put logx=t ....... (1)

Therefore, 1x.dx=dt
=> t2dt.
=> t33+C

Put value of t from eq. (1).
we get,

=> (logx)33+C

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