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Question

Integrate the following function w.r.t x
1x(x6+1)

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Solution

1x(x6+1)dx
=x5x6(x6+1)dx
= let x6=u
6x5dx=du
=16duu(u+1)
=161+uuu(u+1)du
=161u1u+1du
=16(in uin(u+1)).
=in6uu+1
=in6x6x6+1
=inx6x6+1+c




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