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Question

Integrate the following function w.r.t x.
tan4x sec2 xx

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Solution

tan4xsec2xdxx
Let tanx=tsec2x2xdx=dtsec2xxdx=2dt
Therefore,
2t4dt=2t55+c
t=tanx
tan4xsec2xdxx=2tan5x5+c

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