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Question

Integrate the following functions.
2x1+x2dx.

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Solution

Let I=2x1+x2dx
Let 1+x2=t
On differentiating w.r.t.x, we get 2x dx =dtdx=dt2x
I=2xtdt2x=1tdt=log|t|+C=log|1+x2|+C


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