Integrate the following functions. ∫(logx)2xdx.
Let I=∫(logx)2xdx Let log x =t On differentiating w.r.t.x, we get 1x=dtdx→dx=xdt ∴I=∫t2xxdt=∫t2dt=t33+C=(log x)33+C
Integrate the following functions. ∫(1+logx)2xdx.
Integrate the following functions. ∫(x+1)(x+logx)2xdx.
Integrate the following functions. ∫1(1+cotx)dx.
Integrate the following functions. ∫cos√x√xdx.