Question

Integrate the following functions.
$\int se{c}^2(7-4x)dx.$

Answer 1

$\int se{c}^2(7-4x)dx.$
Let $7-4x=t\Rightarrow -4=\frac{dt}{dx}\Rightarrow dx=\frac{dt}{-4}$
$\therefore \int se{c}^2(7-4x)dx=\int se{c}^{2}t.\frac{dt}{-4}=-\frac{1}{4}tant+C=-\frac{1}{4}tan(7-4x)+C$