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Question

Integrate the following functions.
sin (ax+b)cos (ax+b)dx.

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Solution

Let I=sin(ax+b)cos(ax+b)dx
Let sub (ax+b)=t
On differentiating w.r.t.x, we get a cos (ax+b)=dtdx
dx=dtacos(ax+b)I=tcos(ax+b)dtacos(ax+b)=1atdt=1a.t22+c=[sin(ax+b)]22a+C


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