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Question

Integrate the following functions w.r.t. x :
1+tan2xtan2x+3

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Solution

1+tan2xtan2x+3dx=sec2xdx(3)2+tan2x
Let tanx=t
sec2xdx=dt=dt(3)2+t2=logt+t2+3+C=logtanx+tan2x+3+C

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