Integrate the following functions with respect to t: $\int \frac{d t}{(6 t - 1)}$

\frac{1}{6} ln (6 t - 1) + C

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ln (6 t - 1) + C

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- ln (6 t - 1) + C

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- \frac{1}{6} ln (6 t - 1) + C

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Solution

The correct option is B $\frac{1}{6} ln (6 t - 1) + C$
Let $I = \int \frac{d t}{(6 t - 1)}$ $= \frac{ln (6 t - 1)}{6} + C$

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