Question

Integrate the following: $\int (2x-3\cos x+e^x)dx$

Answer 1

$\int (2x-3\cos x+e^x)dx$

$=\int 2xdx-3\int \cos xdx+\int e^{x}dx$

$=2\frac{x^2}{2}-3\sin x+e^x+C$

$=x^2-3\sin x+e^x+C.$

Hence, the answer is $x^2-3\sin x+e^x+C.$