Question

Integrate the following:

sec²x/cosec²x

Answer 1

∫(sec^2x​/cosec^2x)dx
​
∫(1/cos​​^2x)/(1/sin^2x)dx

∫(1/cos​^2x) . (sin^2x/1)dx

∫tan^2x dx

∫(sec^2x-1) dx

tanx - x + c

Hope it helps..

(tan^2x +1=sec^2x
therefore we took ,
tan^2x=sec^2x-1)